Question #218663
A 24kg block is initially at rest on a horizontal surface. A horizontal force of 77N is required to set the block in motion, after which A horizontal force of 65N Is required to keep the block moving with constant speed. Determine the coefficient of static friction.
1
Expert's answer
2021-07-19T09:50:36-0400
μs=7724(9.8)=0.33μk=6524(9.8)=0.28\mu_s=\frac{77}{24(9.8)}=0.33\\\mu_k=\frac{65}{24(9.8)}=0.28\\


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