Answer to Question #218495 in Physics for Rethabile

Question

A motorcycle moves according to the velocity-versus-time graph shown below. What is the distance travelled by the motorcycle during the motion?  

                                                           

Question 17 options:

a) 

  (OA + AB) x BC.

b) 

  (OC + AB) x AD.

c) 

  (AD + BE) x OC.

d) 

No option is correct.

e) 

   (OA + BC) x OC.

Answer 1

Answer: d) No option is correct.

$$D=\frac{1}{2}(OC + AB) AD.$$