Question

A ball of mass 0.5kg is dropped from a height of 0.8m unto a concrete floor and rebounds to a height of 0.5m. calculate the impulse of the floor on the ball

Answer 1

Given:

$m=0.5\;\rm kg$

$h_1=0.8\;\rm m$

$h_2=0.5\;\rm m$

The impulse

$$\Delta p=m|v_f-v_i|=m|\sqrt{2gh_f}-\sqrt{2gh_i}|$$

$$=0.5|\sqrt{2*9.8*0.5}-\sqrt{2*9.8*0.8}|=0.41\: \rm kg*m/s$$