Question

A 10 kg block is pushed 20.0 m up the sloping surface of a plane inclined at an angle of 37^o to the horizontal by a constant force F of 110.0 N acting parallel to the plane as shown in figure 2 below. The coefficient of kinetic friction between the block and plane is 0.25.

Answer 1

$$W_F=110(20)=2200\ J\\W_{fr}=-0.25(10)(9.8)(20)\cos{37}=-391\ J\\ W_{G}=-(10)(9.8)(20)\sin{37}=-1180\ J\\W=2200-1180-391=629\ J$$