6.A car traveling at 20 m/s goes around an unbanked curve in the road which has a radius of 122 m. The acceleration experienced by the car is ___m/s2. (Give your answer with the correct number of significant digits and do not include units)
7.An object traveling in a circle with a radius of 5.0 m has a frequency of 6.0 Hz. The speed of the object is ___x102 m/s. (Give your answer with the correct number of significant digits and do not include units)
8.If the centripetal acceleration on a stone being whirled in a circle at the end of a 1.75 m string is 350 m/s2, the frequency of rotation is ___Hz? (Give your answer with the correct number of significant digits and do not include units)
9.A 1000 kg car enters an unbanked curve of 80 m radius. If the coefficient of friction between the pavement and the car tires is 0.51, the maximum speed which the car can go around the curve is ___m/s. (Give your answer with the correct number of significant digits and do not include units)
6)
"a=\\dfrac{v^2}{r}=\\dfrac{(20\\ \\dfrac{m}{s})^2}{122\\ m}=3.27\\ \\dfrac{m}{s^2}."7) Let's first find the period of the rotation of the object:
Finally, we can find the speed of the object:
8) Let's first find the period of the stone's rotation:
"F_c=ma_c,""ma_c=\\dfrac{4\\pi^2mr}{T^2},""T=\\sqrt{\\dfrac{4\\pi^2r}{a_c}},""T=\\sqrt{\\dfrac{4\\pi^2\\cdot1.75\\ m}{350\\ \\dfrac{m}{s^2}}}=0.444\\ s."Finally, we can find the frequency of rotation:
9)
"F_{c}=F_{fr},""\\dfrac{mv^2}{r}=\\mu mg,""v=\\sqrt{\\mu gr}=\\sqrt{0.51\\cdot9.8\\ \\dfrac{m}{s^2}\\cdot80\\ m}=20\\ \\dfrac{m}{s}."
Comments
Leave a comment