Question

• What is the height of a projectile with initial velocity = "v" and angle = "theta" and gravity = "g"

Answer 1

The height is given as follows (see https://courses.lumenlearning.com/boundless-physics/chapter/projectile-motion/):

$$h = v\cdot t\cdot \sin \theta - \dfrac{gt^2}{2}$$

where $t$ is the time.