Question #215795

The boat is heading due north as it crosses a wide river with a velocity of 10 km/h relative to water. The river has a maintain velocity of 5 km/h due east. Determine the velocity of the boat with respect to an observer on the riverbank.


1
Expert's answer
2021-07-21T09:04:36-0400


We can find the magnitude of the velocity of the boat with respect to an observer on the riverbank from the Pythagorean theorem:


R=vr2+vb2=(5 kmh)2+(10 kmh)2=11.2 kmh.R=\sqrt{v_r^2+v_b^2}=\sqrt{(5\ \dfrac{km}{h})^2+(10\ \dfrac{km}{h})^2}=11.2\ \dfrac{km}{h}.

We can find the direction of the velocity of the boat with respect to an observer on the riverbank from the geometry:


θ=tan1(vrvb),\theta=tan^{-1}(\dfrac{v_r}{v_b}),θ=tan1(5 kmh10 kmh)=26.6 N of E.\theta=tan^{-1}(\dfrac{5\ \dfrac{km}{h}}{10\ \dfrac{km}{h}})=26.6^{\circ}\ N\ of\ E.

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