Question #215278

Two masses 6.0 kg and 9.0 kg are hung from the two ends of a cord which passes over a smooth pulley so that the two masses hang freely. If initially the 9.0 kg mass is 4 meters from the floor, how long will it take this mass to reach the floor after the masses are released? 


1
Expert's answer
2021-07-09T08:31:45-0400
a=969+69.8=2.0ms20.5(2)t2=4t=2 sa=\frac{9-6}{9+6}9.8=2.0\frac{m}{s^2}\\ 0.5(2)t^2=4\\t=2\ s


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