Question #214608

A 5.0 kg toolbox is pulled west across a concrete floor with a rope. The rope makes an angle of 45.0° with the floor. A force of 85.0 N is exerted on the rope, and the force of friction is 15.0 N parallel to the floor. The magnitude of the acceleration of the box is ___m/s^2.(give your answer with the correct number of signification digits and do not include units in your answer)

Note:Let West be positive.


1
Expert's answer
2021-07-07T08:38:49-0400

Let's apply the Newton's Second Law of Motion:


FcosθFfr=ma,Fcos\theta-F_{fr}=ma,a=FcosθFfrm,a=\dfrac{Fcos\theta-F_{fr}}{m},a=85 Ncos4515 N5 kg=9.0 ms2.a=\dfrac{85\ N\cdot cos45^{\circ}-15\ N}{5\ kg}=9.0\ \dfrac{m}{s^2}.

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