Answer to Question #214329 in Physics for frisha

Question

The center of gravity of a non-uniform bamboo pole of length 3m is 1m from its larger end and its weight is 50 Newton. If it is to be supported at its midpoint, what vertical force must be applied at the smaller end of the pole to keep it in a horizontal position? 

Answer 1

$$W(1.5-1)=F(1.5)\\50(0.5)=1.5F\\F=16.7\ N$$