Question #214187

A 10-kg body is suspended by means of a string. Another string is attached to the bottom of the body and a 5-kg body is suspended from the lower end of the lower string. Find the tension in each string


1
Expert's answer
2021-07-09T08:32:15-0400
T2=m2g=5(9.8)=49 NT1=(m2+m1)g=(5+10)(9.8)=147 NT_2=m_2g=5(9.8)=49\ N\\ T_1=(m_2+m_1)g=(5+10)(9.8)=147\ N


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS