Answer to Question #214187 in Physics for ...

Question #214187

A 10-kg body is suspended by means of a string. Another string is attached to the bottom of the body and a 5-kg body is suspended from the lower end of the lower string. Find the tension in each string

Expert's answer

"T_2=m_2g=5(9.8)=49\\ N\\\\\nT_1=(m_2+m_1)g=(5+10)(9.8)=147\\ N"

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