(a)
F=kr2q1q2=9⋅109⋅(0.22+0.12)240⋅10−9⋅30⋅10−9=0.000216 (N)
tanα=−0.20.1=−0.5→α=153.435° (relative to the positive direction of the x-axis)
Fx=0.000216⋅cos153.435°=−1.93⋅10−4 (N)
Fy=0.000216⋅sin153.435°=0.96⋅10−4 (N)
Fp−n=−1.93⋅10−4 i+0.96⋅10−4 j
(b)
Fn−p=−Fp−n
tanα=−0.20.1=−0.5→α=−26.56° (relative to the positive direction of the x-axis)
Fn−p=1.93⋅10−4 i−0.96⋅10−4 j
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