Question #212535

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car.


1
Expert's answer
2021-07-02T09:38:38-0400

Given:

vi=0m/sv_i=0\:\rm m/s

t=5.21st=5.21\:\rm s

d=110md=110\:\rm m

The distance

d=vit+at22d=v_it+\frac{at^2}{2}

Hence,

a=2dt2=2110m(5.21  s)2=8.10m/s2a=\frac{2d}{t^2}=\frac{2*110\:\rm m}{(5.21\;\rm s)^2}=8.10\:\rm m/s^2


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