Question

A parallel plate capacitor is given a charge of 5x10-8C. The space between the plates is filled with dielectric having a permittivity of 5.43x10-11F/m and the electric field within the dielectric is 5.81x106V/m. What is its plate area?

Answer 1

$$A=\frac{q}{E\epsilon}\\A=\frac{5\cdot10^{-8}}{(5.43\cdot10^{-11})(5.81\cdot10^{6})}=1.58\cdot10^{-4}\ m^2$$