A body of mass 2000g falls from rest and has a kinetic energy of 2kJ calculate the height from which the body has fallen
mgh=mv2/2→h=KE/(mg)=2000/(2⋅9.81)≈102 (m)mgh=mv^2/2\to h=KE/(mg)=2000/(2\cdot 9.81)\approx102\ (m)mgh=mv2/2→h=KE/(mg)=2000/(2⋅9.81)≈102 (m)
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