Answer to Question #211550 in Physics for Zohurul

Question

An astronaut on Mars finds that the periodic time of a simple pendulum 1.56 m long is 4.0175 s. Determine the acceleration due to gravity on Mars.

Answer 1

$$T=2\pi\sqrt{\frac{l}{g}}\\4.0175 =2\pi\sqrt{\frac{1.56}{g}}\\g=3.82\frac{m}{s^2}$$