Answer to Question #211049 in Physics for Festus

Question

If the potential difference between two points 2cm apart in an electric field is 20V, the electric field intensity between these points will be around

Answer 1

The electric field intensity is given by

$$E=\frac{V}{d}=\frac{20\:\rm V}{0.02\:\rm m}=1000\:\rm V/m$$