A block slides down a ramp from rest. The block starts at 5.71 m off the ground and has a mass of 3.37 kg. Assuming no friction, what is the speed of the block at the bottom of the ramp?
mgh=mv2/2→v=2gh=2⋅9.81⋅5.71=10.58 (m/s)mgh=mv^2/2\to v=\sqrt{2gh}=\sqrt{2\cdot9.81\cdot5.71}=10.58\ (m/s)mgh=mv2/2→v=2gh=2⋅9.81⋅5.71=10.58 (m/s) . Answer
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