Answer to Question #210067 in Physics for pumpkin

Question

A particle with a charge of -1.24x10^-8 C is moving with instantaneous velocity (1.49x10^4m/s) î +(-3.85x10^4m/s) ĵ.​ What is the force exerted on this particle by a magnetic field

(a) (1.40T)î+ (-2.30T)k̂

(b) (-1.25T)î+ (2.00T)ĵ + (-3.50T)k̂

Answer 1

a)

$$\bold{F}=(-1.24\cdot10^{-8})(1.49\cdot10^{4},-3.85\cdot10^{4},0)\times\\(1.4,0,-2.3)\\=(-11,-4.2,-6.7)\cdot10^{-4}N$$

b)

$$\bold{F}=(-1.24\cdot10^{-8})(1.49\cdot10^{4},-3.85\cdot10^{4},0)\times\\(-1.25,2,-3.5)\\=(-16.7,-6.5,2.3)\cdot10^{-4}N$$