Answer to Question #210032 in Physics for Tarik

Question

A vial contains 2000 MBq of Technetium-99m on the 18th June 2014 at 06:00. How much will it contain at 07:00 on the 19th June 2014? Please input your answer inBq and Ci.

Answer 1

$$A(25)=1900\cdot2^{-\frac{25}{6}}=105.8 MBq$$

$$A=105.8⋅10 ^ 6 Bq\\=105.8⋅10 ^ 6 ⋅2.7⋅10 ^ {−11} Ci≈2.86\ mCi$$