The breaking strength of a string is 500N.
Find the maximum speed that it can attain if a 1.5kg ball is attached at one end while the
other is held stationary and is whirled in a
circle. The string is 0.65m long.
T=mv2/r→v=Tr/m=500⋅0.65/1.5=14.72 (m/s)T=mv^2/r\to v=\sqrt{Tr/m}=\sqrt{500\cdot 0.65/1.5}=14.72\ (m/s)T=mv2/r→v=Tr/m=500⋅0.65/1.5=14.72 (m/s) . Answer
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