The breaking strength of a string is 500N.
Find the maximum speed that it can attain if a 1.5kg ball is attached at one end while the
other is held stationary and is whirled in a
circle. The string is 0.65m long.
"T=mv^2\/r\\to v=\\sqrt{Tr\/m}=\\sqrt{500\\cdot 0.65\/1.5}=14.72\\ (m\/s)" . Answer
Comments
Leave a comment