Answer to Question #209562 in Physics for Dolp

Question

A gas at a volume of V₀ in a container at pressure P₀ is compressed to one-fifth of its volume. What will be its pressure if the magnitude of its original temperature T is constant?

Answer 1

Given:

Initial volume $V_0$

Final volume: $V_0/5$

Initial pressure: $P_0$

$T_0=T_1$

According to the combined gas law:

$$\frac{P_0V_0}{T_0}=\frac{P_1V_1}{T_1},\\\space\\ P_0V_0=P_1V_1,\\\space\\ P_0V_0=P_1(V_0/5),\\\space\\ P_1=5P_0.$$