The horn of Ms Brown’s VW has a frequency of 400 Hz. What frequency would her 3U math class hear if she honks the horn while driving at 50 km/h on a 23 C day?
a) toward the class
b) away from the class
a) ν=ν0cc−u=400⋅345.3345.3−13.89=416.76 (Hz)\nu=\nu_0\frac{c}{c-u}=400\cdot\frac{345.3}{345.3-13.89}=416.76\ (Hz)ν=ν0c−uc=400⋅345.3−13.89345.3=416.76 (Hz)
b) ν=ν0cc+u=400⋅345.3345.3+13.89=384.53 (Hz)\nu=\nu_0\frac{c}{c+u}=400\cdot\frac{345.3}{345.3+13.89}=384.53\ (Hz)ν=ν0c+uc=400⋅345.3+13.89345.3=384.53 (Hz)
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