760 J of heat is used to increase the temperature of 400g of copper block from 30 ℃ to 35 ℃. What is the specific heat capacity of the copper block?
"Q=cm(t_2-t_1)\\to c=\\frac{Q}{m(t_2-t_1)}=\\frac{760}{0.4\\cdot(35-30)}=380\\ (J\/(kg\\cdot K))" . Answer
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