(a) Let's first find the pressure the brick exerts when standing on its largest face:
P=AF=abmg=0.15 m⋅0.3 m2 kg⋅9.8 s2m=435.5 Pa.(b) Let's find the pressure the brick exerts when standing on two other faces:
P=AF=acmg=0.15 m⋅0.075 m2 kg⋅9.8 s2m=1742 Pa,P=AF=bcmg=0.3 m⋅0.075 m2 kg⋅9.8 s2m=871 Pa.
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