Question #209176

A 2.0-kg brick has the dimensions 7.5 cm x 15 cm x 30 cm. Find the pressures 

exerted by the brick on a table when it is resting on its various faces


1
Expert's answer
2021-06-21T11:42:03-0400

(a) Let's first find the pressure the brick exerts when standing on its largest face:


P=FA=mgab=2 kg9.8 ms20.15 m0.3 m=435.5 Pa.P=\dfrac{F}{A}=\dfrac{mg}{ab}=\dfrac{2\ kg\cdot9.8\ \dfrac{m}{s^2}}{0.15\ m\cdot0.3\ m}=435.5\ Pa.

(b) Let's find the pressure the brick exerts when standing on two other faces:


P=FA=mgac=2 kg9.8 ms20.15 m0.075 m=1742 Pa,P=\dfrac{F}{A}=\dfrac{mg}{ac}=\dfrac{2\ kg\cdot9.8\ \dfrac{m}{s^2}}{0.15\ m\cdot0.075\ m}=1742\ Pa,P=FA=mgbc=2 kg9.8 ms20.3 m0.075 m=871 Pa.P=\dfrac{F}{A}=\dfrac{mg}{bc}=\dfrac{2\ kg\cdot9.8\ \dfrac{m}{s^2}}{0.3\ m\cdot0.075\ m}=871\ Pa.

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