Question #208806

A point charge q=5nC

q=5nC is moving in the x-y plane with velocity v

⃗ 

=(1.1×10

8

m/s)i

^

+(1.2×10

8

m/s)j

^

v→=(1.1×108m/s)i^+(1.2×108m/s)j^ through a magnetic field B

⃗ 

=(1.2T)i

^

+(2.7T)k

^

B→=(1.2T)i^+(2.7T)k^. What is the magnitude of the magnetic force on q

q (in Newtons)? Only give the numerical value.


1
Expert's answer
2021-06-21T11:42:26-0400

F=q[v,B]=1.62i  1.485j  0.72k\vec F=q[\vec v,\vec B]=1.62\vec i\ -\ 1.485\vec j\ -\ 0.72\vec k


F=1.622+1.4852+0.722=2.31 (N)|\vec F|=\sqrt{1.62^2+1.485^2+0.72^2}=2.31\ (N)



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