Answer to Question #208333 in Physics for Erin

Question

A 2.8 kg block slides on a frictionless 20 degree inclined plane. A force of 23 N acting parallel to the incline and up the incline is applied to the block. The block is moving upward. What is the acceleration of the block?

Answer 1

Let's apply Newton's Second Law of Motion:

$F-mgsin\theta=ma,$ $a=\dfrac{F-mgsin\theta}{m},$ $a=\dfrac{23\ N-2.8\ kg\cdot9.8\ \dfrac{m}{s^2}\cdot sin20^{\circ}}{2.8\ kg}=4.86\ \dfrac{m}{s^2}.$