Answer to Question #207741 in Physics for Diva

Question

A 0.20 kg mass attached to the end of a spring is whirled in a vertical circle by a student. At some positions, the mass experiences a downward force of -60j N and a horizontal force 38i N. Determine it's acceleration in this position.

Answer 1

$$a_x=\frac{38}{0.2}=190\frac{m}{s^2}\\ a_y=-\frac{60}{0.2}=-300\frac{m}{s^2}\\ a=\sqrt{190^2+300^2}=355\frac{m}{s^2}\\\theta=360-\arctan{\frac{300}{190}}=302\degree$$