Question

An ion accelerated through a potential difference of 115V experiences 

an increase in potential energy of 7.37×10-17J. 

Calculate the charge on the ion.

Answer 1

$$\Delta V=\dfrac{PE}{q},$$ $$q=\dfrac{PE}{\Delta V}=\dfrac{7.37\cdot10^{-17}\ J}{115\ V}=6.41\cdot10^{-19}\ C.$$