Question #206725

A man has five 60W bulbs and a 210W water heater in his apartment. If the bulbs and the water heater are switched on four hours daily and the cost of electricity is 1.20 per KWhr. Calculate his bill for 30 days


1
Expert's answer
2021-06-14T08:18:14-0400
E=(5⋅60+210)(4)(30)=61.2 kWhP=61.2(1.2)=73.44E=(5\cdot60+210)(4)(30)=61.2\ kW h\\ P=61.2(1.2)=73.44


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