Answer to Question #206414 in Physics for Luyanda

Question

the drawing, the weight of the block on the table is 422 N and that of the hanging block is 185 N. Ignoring all 

frictional effects and assuming the pulley to be massless, 

Answer 1

So, assume that

In the drawing, the weight of the block on the table is 422 N and that of the hanging block is 185 N. Ignoring all frictional effects and assuming the pulley to be massless, find (a) the acceleration of the two blocks and (b) the tension in the cord.

$m_1=422/9.81=43\ (kg)$

$m_2=185/9.81=18.9\ (kg)$

(a) $m_1a=T$ and $m_2g-T=m_2a\to 185-T=m_2a$

$185-m_1a=m_2a\to a=\frac{185}{m_1+m_2}=\frac{185}{43+18.9}=2.99\ (m/s^2)$

(b) $T=m_1a=43\cdot2.99=128.5\ (N)$