Question

A train of total mass 300 tonnes (3×10^5kg) is moving up an incline of angle ∆ to the horizontal, where sin∆=1/280.The resistance to motion is 3000N and the train is accelerating at 0.2ms^-2. Find (a)the driving force of the engine. (b) the power exerted by the driving force at the moment when the speed is10ms^-1.

Answer 1

a)

$ma=F-mgsin\Delta-F_{res}$

$F=ma+mgsin\Delta+F_{res}=0.2\cdot3\cdot10^5+9.8\cdot3\cdot10^5/280+3000=73500\ N$

b)

$P=Fv=73500\cdot10=735\ kW$