Question

a 150g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.6 m .the ball makes 2 revolutions in a second what is it’s centripal acceleration

Answer 1

$a=v^2/r=\omega^2r$

$2\ (rev/s)=4\pi\ (rad/s)$ . So,

$a=\omega^2r=(4\pi)^2\cdot0.6=94.75\ (m/s^2)$ . Answer