Question

charge is flowing through a conducter at the rate of 40C/min.If 30 J of electrical energy are converted to heat in 30s.What is the potantial drop across the conducter?

Answer 1

The electrical energy is

$$E=Pt$$

The power is

$$P=IV,\\ E=IVt$$

The current is 40 C/min, or 0.667 C/s, which is 0.667 A.

The voltage drop:

$$V=\frac{E}{It}=\frac{30}{0.667·30}=1.5\text{ V}.$$