In a parallel circuit a 50 ohm hairdryer has 2.4 amps of current flowing through it. How much current is flowing through a light bulb which is in parallel with the hairdryer?
V=IR=2.4⋅50=120 (V)V=IR=2.4\cdot50=120\ (V)V=IR=2.4⋅50=120 (V)
Suppose that the power of the lamp is 12 (W)12\ (W)12 (W) . So,
I=P/V=12/120=0.1 (A)I=P/V=12/120=0.1\ (A)I=P/V=12/120=0.1 (A) . Answer
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