A homogeneous triangular lamina has the vertices (0, 0), (3, 0) and (0, 3). Obtain the coordinates of the centre of mass of the lamina.
xc=x1+x2+x33=0+3+03=1x_c=\frac{x_1+x_2+x_3}{3}=\frac{0+3+0}{3}=1xc=3x1+x2+x3=30+3+0=1
yc=y1+y2+y33=0+0+33=1y_c=\frac{y_1+y_2+y_3}{3}=\frac{0+0+3}{3}=1yc=3y1+y2+y3=30+0+3=1 . So,
the coordinates of the centre of mass of the lamina (1,1)(1,1)(1,1) . Answer
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