Find the initial temperature of 0.355 kg of glycerin if it is heated by 600 J of heat to produce a final temperature of 91℃.?
Q=cm(t2−t1)→t1=(Q−cmt2)/cm=Q=cm(t_2-t_1)\to t_1=(Q-cmt_2)/cm=Q=cm(t2−t1)→t1=(Q−cmt2)/cm=
=(600−2400⋅0.355⋅91)/(−2400⋅0.355)=90.3°=(600-2400\cdot0.355\cdot91)/(-2400\cdot0.355)=90.3°=(600−2400⋅0.355⋅91)/(−2400⋅0.355)=90.3° . Answer
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