Question #203968

25. A partly full paint can has 2.75 liters of paint left in it. What is volume of the paint in cubic centimeters? (3)

A) 2.75 x 10-3 cm3 C) 275 x 10-3 cm3 E) 27.5 x 103 cm3

B) 2.75 cm3 D) 2.75 x 103 cm3 


26. Calculate the resultant of the four forces working on an object:

25 N 20° W of N

60 N 18° S of W

45 N W

35 N 49° E of N

Use the perpendicular component method. Express the answer in unit vector notation.  (6)



1
Expert's answer
2021-06-14T08:19:45-0400

25. 1 L is 1000 mL, 1 mL is 1 cm3, so, 2.75 L is 2750 cm3, or 2.75·103 cm3

26. Find the components of each force assuming E is +x and N is +y:


F1x=25sin20°=8.55N.F2x=60cos18°=57.1N.F3x=45sin45°=31.8N.F4x=35sin49°=26.4N. F1y=25cos20°=23.5N.F2y=60sin18°=18.5N.F3y=45cos45°=31.8N.F4y=35cos49°=23N.F_{1x}=-25\text{sin}20°=-8.55\text N.\\ F_{2x}=-60\text{cos}18°=-57.1\text N.\\ F_{3x}=45\text{sin}45°=31.8\text N.\\ F_{4x}=35\text{sin}49°=26.4\text N.\\ \\\space\\ F_{1y}=25\text{cos}20°=23.5\text N.\\ F_{2y}=-60\text{sin}18°=-18.5\text N.\\ F_{3y}=45\text{cos}45°=31.8\text N.\\ F_{4y}=35\text{cos}49°=23\text N.\\

The resultant:


Fxi+Fyj=(F1x+F2x+F3x+F4x)i++(F1y+F2y+F3y+F4y)j==[7.45i+59.8j]N.F_xi+F_yj=(F_{1x}+F_{2x}+F_{3x}+F_{4x})i+\\+(F_{1y}+F_{2y}+F_{3y}+F_{4y})j=\\ =-[7.45i+59.8j]\text{N}.


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