Answer to Question #203674 in Physics for Cheezy

Question

A car accelerates uniformly from rest to a speed of 36 km/hr in 5 seconds. The distance covered by the car in the first 10 seconds is:

Answer 1

$v=at\to a=v/t=10/5=2\ (m/s^2)$

$s=at^2/2=2\cdot10^2/2=100\ (m)$ - if the car moves with acceleration within $10 \ s$

$s=at^2/2+vt=2\cdot5^2/2+10\cdot5=75\ (m)$ - if the car moves with acceleration for $5 \ s$ , and

evenly for the next $5 \ s$ .