Question

what is the internal energy of the 1700 kg lead considering that its standard coefficient of thermal and specific heat that has made a 6 m cube of lead heated from 30 degrees to 300 degrees celsius

Answer 1

The internal energy is given as follows:

$$Q = mc\Delta T$$

where $m = 1700 kg$ is the mass of hte cube, $c = 1280 \space \dfrac{J}{kg\cdot \degree C}$ is the specific heat capacity of lead, $\Delta T = 300\degree C - 30\degree C = 270\degree C$ is the change in temperature. Thus, obtain:

$$Q = 1700\cdot 1280 \cdot 270 \approx 588\times 10^6 J = 588MJ$$

Answer. 588 MJ.