A 7.0 Ohms resistor is connected in the series with another resistor and a 4.5 V battery. The current is 0.60 A. calculate the value of the unknown resistance.
V=I(r+rx)→4.5=0.6⋅7+0.6⋅rx→rx=0.5 (Ω)V=I(r+r_x)\to4.5=0.6\cdot7+0.6\cdot r_x\to r_x=0.5\ (\Omega)V=I(r+rx)→4.5=0.6⋅7+0.6⋅rx→rx=0.5 (Ω) . Answer
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