Question #202010

What is the impulse for a force of 40 newtons being applied to an object for 5 seconds?


1
Expert's answer
2021-06-07T09:29:20-0400

F=ΔpΔt→Δp=F⋅Δt=40⋅5=200 (N⋅s)F=\frac{\Delta p}{\Delta t}\to \Delta p= F\cdot \Delta t=40\cdot5=200\ (N\cdot s) . Answer

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