A car of mass 500 kg is moving at 24 m/s.a lion of mass 100 kg drops on to the roof of the car from an overhanging branch.show that the car will slow down to 20 m/s
According to the law of conservation of momentum
"mv=(M+m)u\\to u=\\frac{mv}{M+m}=\\frac{500\\cdot24}{100+500}=20\\ (m\/s)" . Answer
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