Answer to Question #201476 in Physics for Aljames Teraza Bar

Question

2. AN OBJECT IS THROWN WITH A SPEED OF 60M/SEC IN A DIRECTION 60 O ABOVE THE HORIZONTAL. FIND;

A. THE HEIGHT IT RISES

B. THE TOTAL TIME OF FLIGHT

C. THE HORIZONTAL RANGE.

Answer 1

a)

$$h=\frac{60^2\sin^2{60}}{2(9.8)}=138\ m$$

b)

$$t=2\frac{60\sin{60}}{(9.8)}=10.6\ s$$

c)

$$R=\frac{60^2\sin{120}}{(9.8)}=318\ m$$