The photoelectric minimum (threshold) frequency for a material is 3.3 x 10-7 m. What is the work function for this material?
A. 9.2 eV
B. 5.6 eV
C. 3.8 eV
D. 6.1 eV
E. 4.9 eV
hc/λ=W→W=6.62⋅10−34⋅3⋅108/3.3⋅10−7=6.018⋅10−19 (J)≈3.8 (eV)hc/\lambda=W\to W=6.62\cdot10^{-34}\cdot3\cdot10^8/3.3\cdot10^{-7}=6.018\cdot10^{-19}\ (J)\approx3.8\ (eV)hc/λ=W→W=6.62⋅10−34⋅3⋅108/3.3⋅10−7=6.018⋅10−19 (J)≈3.8 (eV)
C. 3.8 eV . Answer
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