The photoelectric minimum (threshold) frequency for a material is 2.23 x 1015 Hz. What is the work function for this material?
A. 8.3 eV
B. 4.9 eV
C. 11 eV
D. 9.8 eV
E. 9.2 eV
W=hν=6.62⋅10−34⋅2.23⋅1015=14.76⋅10−19 (J)≈9.2 (eV)W=h\nu=6.62\cdot10^{-34}\cdot2.23\cdot10^{15}=14.76\cdot10^{-19}\ (J)\approx9.2\ (eV)W=hν=6.62⋅10−34⋅2.23⋅1015=14.76⋅10−19 (J)≈9.2 (eV)
E. 9.2 eV . Answer
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