The work function of a certain material is 4.9 eV. What is the photoelectric minimum (threshold) frequency for this material?
A. 1.18 x 1015 Hz
B. 2.23 x 1015 Hz
C. 9.01 x 1014 Hz
D. 3.48 x 1015 Hz
E. 2.56 x 1015 Hz
W=hν→ν=W/h=4.9⋅1.6⋅10−19/(6.62⋅10−34)=1.18⋅1015 (Hz)W=h\nu\to\nu=W/h=4.9\cdot1.6\cdot10^{-19}/(6.62\cdot10^{-34)}=1.18\cdot10^{15}\ (Hz)W=hν→ν=W/h=4.9⋅1.6⋅10−19/(6.62⋅10−34)=1.18⋅1015 (Hz)
A. 1.18⋅1015 (Hz)1.18\cdot10^{15}\ (Hz)1.18⋅1015 (Hz) . Answer
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