a brick is thrown forward on the ground with a speed of 28 m/s. the coefficient of sliding friction between the brick and the ground is 0.25. compute the time and the distance the brick will travel before coming to rest
Ff=ma→μmg=ma→a=μg=0.25⋅9.8=2.45 (m/s2)F_f=ma\to \mu mg=ma\to a=\mu g=0.25\cdot9.8=2.45\ (m/s^2)Ff=ma→μmg=ma→a=μg=0.25⋅9.8=2.45 (m/s2)
v=v0−at→t=v0/a=28/2.45=11.43 (s)v=v_0-at\to t=v_0/a=28/2.45=11.43\ (s)v=v0−at→t=v0/a=28/2.45=11.43 (s)
s=v02/(2a)=282/(2⋅2.45)=160 (m)s=v_0^2/(2a)=28^2/(2\cdot2.45)=160\ (m)s=v02/(2a)=282/(2⋅2.45)=160 (m)
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