Question

A 300kg particle has a velocity of (3.00i - 4.00j) m/s.

a). Find it's x and y components of momentum.

b). Find the magnitude and direction of its momentum.

Answer 1

a)

$$p_x=300(3)=900\frac{kgm}{s}\\p_y=-300(4)=-1200\frac{kgm}{s}$$

b)

$$p=\sqrt{900^2+1200^2}=1500\frac{kgm}{s}\\\theta=-\arctan{\frac{4}{3}}=-53\degree$$