A converging lens has a focal length of 30 cm. A 5 cm tall candle is placed at a distance of 10 cm in front of the lens. Determine the image distance.
1/di+1/do=1/f→1/di=1/f−1/do=1/0.3−1/0.1=−6.6667→1/d_i+1/d_o=1/f\to1/d_i=1/f-1/d_o=1/0.3-1/0.1=-6.6667\to1/di+1/do=1/f→1/di=1/f−1/do=1/0.3−1/0.1=−6.6667→
di=1/(−6.6667)=−0.15 (m)=−15 (cm)d_i=1/(-6.6667)=-0.15\ (m)=-15\ (cm)di=1/(−6.6667)=−0.15 (m)=−15 (cm) . Answer
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